(6x^2-3x-17)/(3x-1)

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Solution for (6x^2-3x-17)/(3x-1) equation:


D( x )

3*x-1 = 0

3*x-1 = 0

3*x-1 = 0

3*x-1 = 0 // + 1

3*x = 1 // : 3

x = 1/3

x in (-oo:1/3) U (1/3:+oo)

(6*x^2-(3*x)-17)/(3*x-1) = 0

(6*x^2-3*x-17)/(3*x-1) = 0

6*x^2-3*x-17 = 0

6*x^2-3*x-17 = 0

DELTA = (-3)^2-(-17*4*6)

DELTA = 417

DELTA > 0

x = (417^(1/2)+3)/(2*6) or x = (3-417^(1/2))/(2*6)

x = (417^(1/2)+3)/12 or x = (3-417^(1/2))/12

(x-((3-417^(1/2))/12))*(x-((417^(1/2)+3)/12)) = 0

((x-((3-417^(1/2))/12))*(x-((417^(1/2)+3)/12)))/(3*x-1) = 0

( x-((3-417^(1/2))/12) )

x-((3-417^(1/2))/12) = 0 // + (3-417^(1/2))/12

x = (3-417^(1/2))/12

( x-((417^(1/2)+3)/12) )

x-((417^(1/2)+3)/12) = 0 // + (417^(1/2)+3)/12

x = (417^(1/2)+3)/12

x in { (3-417^(1/2))/12, (417^(1/2)+3)/12 }

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